CAT 2021 Exam Question Papers Slot 1 | CAT Quants

CAT Quantitative Aptitude | CAT 2021 Question Papers

CAT Question Papers: Solving CAT Question Papers from prior years will give CAT 2022 applicants invaluable insight into the examination format, question pattern, and level of difficulty. The CAT 2021 exams were held in three slots.
It is important for CAT preparation to examine old CAT Exam, Question Paper. In order to overcome the difficulties, they encounter when preparing for the CAT, aspirants must use a variety of strategies.


  • By solving CAT Exam previous year question papers, aspirants learn about their own strengths and weaknesses. This allows them to plan their preparation accordingly.
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  • CAT aspirants can benefit from numerous study materials and engaging video lessons available at Pathfinder For Me, including Free Download CAT Exam E-Books. Aspirants for the CAT test will get closer to passing the CAT 2022 exam with the help of these CAT question papers with solution PDF.

The best resource for CAT preparation is CAT question papers. Solving previous year’s CAT question papers helps candidates understand the CAT Exam Pattern, types of questions, question weightage, important topics, etc.

All CAT 2021 Quantitative aptitude questions have detailed answer keys and solutions provided by our experts. Watch the videos below to learn the fastest ways to answer the questions:


Suppose hospital A admitted 21 less Covid infected patients than hospital B, and all eventually recovered. The sum of recovery days for patients in hospitals A and B were 200 and 152, respectively. If the average recovery days for patients admitted in hospital A was 3 more than the average in hospital B then the number admitted in hospital A was


    Assume that hospital A admitted  patients and hospital B did ( + 21) patients.

             Then, average recovery days (hospital A)  = 200 over a, and

             Average recovery days (hospital B) = fraction numerator 152 over denominator a plus 21 end fraction

             According to the question,

                200 over a -  fraction numerator 152 over denominator a plus 21 end fraction  = 3

    => 200(a+21) – 152 a = 3 a(a+21)

    => 3 a2 + 15 a – 4200 = 0   or    a2 + 5 a – 1400 = 0

    => (a + 40)( a – 35) = 0      => a = 35,  ignoring negative value

    Ans: (35)

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