CAT 2021 Exam Question Papers Slot 1 | CAT Quants

CAT Quantitative Aptitude | CAT 2021 Question Papers

CAT Question Papers: Solving CAT Question Papers from prior years will give CAT 2022 applicants invaluable insight into the examination format, question pattern, and level of difficulty. The CAT 2021 exams were held in three slots.
It is important for CAT preparation to examine old CAT Exam, Question Paper. In order to overcome the difficulties, they encounter when preparing for the CAT, aspirants must use a variety of strategies.


  • By solving CAT Exam previous year question papers, aspirants learn about their own strengths and weaknesses. This allows them to plan their preparation accordingly.
  • The secret to passing any exam is practice. Hence, by studying CAT exam papers over the last 5 to 10 years, you can attempt 500+ questions of all types and levels of difficulty.
  • They can identify important topics by asking questions that have been asked repeatedly over time.
  • CAT aspirants can benefit from numerous study materials and engaging video lessons available at Pathfinder For Me, including Free Download CAT Exam E-Books. Aspirants for the CAT test will get closer to passing the CAT 2022 exam with the help of these CAT question papers with solution PDF.

The best resource for CAT preparation is CAT question papers. Solving previous year’s CAT question papers helps candidates understand the CAT Exam Pattern, types of questions, question weightage, important topics, etc.

All CAT 2021 Quantitative aptitude questions have detailed answer keys and solutions provided by our experts. Watch the videos below to learn the fastest ways to answer the questions:


The amount Neeta and Geeta together earn in a day equals what Sita alone earns in 6 days. The amount Sita and Neeta together earn in a day equals what Geeta alone earns in 2 days. The ratio of the daily earnings of the one who earns the most to that of the one who earns the least is

  1. 7 : 3

  2. 11 : 3

  3. 11 : 7

  4. 3:2


If daily earnings of Neeta, Geeta, and Sita be N, G, and S respectively,

         N + G = 6 S     …..(1)

         S + N = 2 G     …..(2)

         Subtracting  equation  (2) from (1),

         G – S = 6 S – 2 G           =>  3 G = 7 S     =>  S = (3/7) G   …(3)

         Substituting for S in (1),

         N + G = (18/7) G           => N = (11/7) G                           ….(4)

         Comparing  (3) and (4), it is clear that Neeta earns the most and Seeta  earns the least

         Required ratio = fraction numerator begin display style bevelled 11 over 7 end style over denominator begin display style bevelled 3 over 7 end style end fraction  = 11: 3


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